ln^2(3x+1)=f(x)

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Solution for ln^2(3x+1)=f(x) equation: 


Simplifying
ln2(3x + 1) = f(x)

Reorder the terms:
ln2(1 + 3x) = f(x)
(1 * ln2 + 3x * ln2) = f(x)
(1ln2 + 3ln2x) = f(x)

Multiply f * x
1ln2 + 3ln2x = fx

Solving
1ln2 + 3ln2x = fx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1fx + 1ln2 + 3ln2x = fx + -1fx

Combine like terms: fx + -1fx = 0
-1fx + 1ln2 + 3ln2x = 0

The solution to this equation could not be determined.

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